Sharp Inequalities for the Euler-Mascheroni Constant
2014-09-17-,-
-, -
(School of Mathematics and Informatics, Henan Polytechnic University,Jiaozuo, Henan 454000, China)
1 Introduction
The Euler-Mascheroni constantγ=0.577215664… is defined as the limit of the sequence
Dn=Hn-lnn,
(1.1)
whereHndenotes thenth harmonic number, defined forn∈N∶={1,2,3,…} by
Several bounds forDn-γhave been given in the literature [1-7]. For example, the following bounds forDn-γwas established in [2,3]:
The convergence of the sequenceDntoγis very slow. By changing the logarithmic term lnnin (1.1), some quicker approximations to the Euler-Mascheroni constant were established in [8-16]. For example, DeTemple[8]proved in 1993 that
(1.2)
where
Recently, Chen[9]obtained the following sharp form of the inequality (1.2): For all integersn≥1, then
(1.3)
with the best possible constants
In 1997, Negoi[10]proved that the sequence
(1.4)
is strictly increasing and convergent toγ. Moreover, the author proved that
(1.5)
Recently, Chen and Mortici[11]obtained the following sharp form of the inequality (1.5): For all integersn≥1, then
(1.6)
with the best possible constants
Also in [11], the authors proved that forn∈N,
(1.7)
with the best possible constants
In this paper, by changing the logarithmic term ln(4n) in (1.7), we present sharp inequality for the Euler-Mascheroni constant.
TheoremFor all integersn≥1, let
Then
(1.8)
with the best possible constants
2 Lemmas
The Euler-Mascheroni constantγis deeply related to the gamma functionΓ(z) thanks to the Weierstrass formula:
The logarithmic derivative of the gamma function:
is known as the psi (or digamma) function. The successive derivatives of the psi functionψ(z):
are called the polygamma functions.
The following lemmas are required in our present investigation.
(2.1)
and
(2.2)
with
whereBkare Bernoulli numbers defined by
From (2.2), we obtain forx>0,
(2.3)
Lemma2Forx≥2, let
(2.4)
Then
(2.5)
and
(2.6)
ProofConsider the functionF(x) defined by
Applying the second inequality in (2.3), we obtain that forx≥2,
with
G(x) =38149418294893+309603910615856(x-2)+580284311908092(x-2)2
+482792790621464(x-2)3+204943551011683(x-2)4
+43378335655200(x-2)5+3614861304600(x-2)6.
Hence,F′(x)<0 forx≥2, and we have
This means that the inequality (2.5) holds forx≥2.
It is well-known that letx>-1, then forα<0 orα>1,
(1+x)α≥1+αx,
(2.7)
the equal sign holds if and only ifx=0.
Applying the inequality (2.7), we obtain from (2.5) that forx≥2,
The proof of Lemma 2 is complete.
3 Proof of Theorem
It is well-known[18,p.258]that
Thus, the inequality (1.8) can be written as
θ1≥f(n)>θ2,n∈N,
where
withh(x) defined in (2.4).
asx→∞. It follows from (2.1) that
We then obtain that
Further, we find that
which implies
Direct computation yields
In order to prove our Theorem, it suffices to show that the sequence (f(n)) is strictly decreasing forn∈N. Differentiatingf(x) and applying (2.3) and (2.6) yield, forx≥4,
where
g(x) =10010655865312+21800267033016(x-4)+17008581298487(x-4)2
+6513883623680(x-4)3+1326804177680(x-4)4
+137952967680(x-4)5+5748040320(x-4)6.
Hence,f′(x)<0 forx≥4.
Direct computation yields
f(1)=0.114501384…,f(2)=0.078266339…,
f(3)=0.057606492…,f(4)=0.045564402….
Hence, the sequence (f(n)) is strictly decreasing for alln∈N. The proof is complete.
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