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Existence of Solutions for Infinity-Point Nonlinear Fractional Boundary Value Problem at Resonance

2015-08-07LIURuijuan刘瑞娟JINRan金冉

LIU Rui-juan(刘瑞娟),JIN Ran(金冉)

1 School of Fundamental Studies,Shanghai University of Engineering Science,Shanghai201620,China

2 College of Information Science and Technology,Donghua University,Shanghai201620,China

Existence of Solutions for Infinity-Point Nonlinear Fractional Boundary Value Problem at Resonance

LIU Rui-juan(刘瑞娟)1,2,JIN Ran(金冉)2

1 School of Fundamental Studies,Shanghai University of Engineering Science,Shanghai201620,China

2 College of Information Science and Technology,Donghua University,Shanghai201620,China

A class of the boundary value problem for fractional order nonlinear differential equation with Riemann-Liouville fractional derivative on the half line was studied.By using the coincidence degree theory due to M awhin and constructing the suitable operators,the existence theorem of at least one solution has been established.An exam ple is given to illustrate our result.

fractional differential equation;infinity-point boundary value problem;coincidence degree theorem;resonance;half line

Introduction

Fractional differential equation can describe many phenomena in various fields of science and engineering such as control,porous media,electrochemistry,viscoelasticity,and electromagnetic.There are a large number of papers dealing with the solvability of nonlinear fractional differentialequations. For details,see Refs.[1-4]and the references therein. References[5-10]considered boundary value problems for fractional differential equations.Recently,various types of multi-point boundary value problems for fractional differential equations at resonance on a bounded domain have been analyzed by Kosmatov[5],Jiang[6],Bai[7],Baiand Zhang[8-9].

However,there are few papers which consider the boundary value problem at resonance for infinity-pointnonlinear fractional equation on a half line.The follow ing fractional differential equation at resonance with multi-point boundary value problem on a half-line was discussed in Ref.[10]:

where1<α≤2,η>0,f:[0,+∞)××→is an SCarathéodory function,andis the standard Riemann- Liouville fractional derivative.

Enlightened by the literatures above,in this paper,we study the existence of solutions for the follow ing fractional differential equations at resonance with infinity-point boundary value problem on an unbounded domain:

where 1<α≤2,0<η1<η2<…<ηi<…,f:[0,+∞)××→is an SCarathéodory function,andis the standard Riemann- Liouville fractional derivative.Moreover,we suppose the follow ing resonance condition:

This condition leads that the fractional differential operatorin Eq.(1)has a nontrivial kernel:

The boundary value problems(1)with such critical condition (2)is so-called problems at resonance.Our main tool is the well-known coincidence degree of Mawhin[11].

1 Prelim inaries

First,Let us briefly recall some notations and an abstract existence result.

Assume Y and Z are Banach spaces,L∈B(Y,Z),then L is called a Fredholm mapping,if the follow ing conditions are satisfied:(1)Im L is a closed subset of Z;(2)dim Ker L<+∞;(3)co dim Im L<+∞.We set the index of L ind L= dim Ker L-co dim Im L,if dim Ker L=co dim Im L<+∞,then L is called a Fredholm mapping of index zero.And if L isa Fredholm mapping of index zero,there exist linear continuous projectors P:Y→Y and Q:Z→Z such that Im P=Ker L,Ker Q=Im L,and Y=Ker L⊕Ker P,Z=Im L⊕Im Q.Then it follows that L|domL∩KerP:dom L∩Ker P→Im L is invertible. We denote the inverse of this map by KP:Im L→dom L∩Ker P.The generalized inverse of thismap is KP,Q:Y→dom L∩Ker P,KP,Q=KP(I-Q).

Assume L:dom L⊂Y→Z is a Fredholm mapping,ifΩis an open bou-nded subset of Y,the map N will be called L-compact onΩif QN:Ω→Z is bounded and KP,QN:Ω→Y is compact.For Im Q is isomorphic to Ker L,there exists an isomorphism JNL:Im Q→Ker L.

Themain toolwe used is Theorem 2.4 of Ref.[11].

Theorem 1[11]Assume-L is a Fredholm mapping of index zero and N is L-compact onΩ,whereΩis an open bounded subset of Y.Suppose the follow ing conditions are satisfied:

(1)Ly≠λNy for each(y,λ)∈[(dom LKer L)∩∂Q]×(0,1);

(2)Ny∉Im L for each y∈Ker L∩∂Q;

(3)deg(JNLQN|KerL,Ω∩Ker L,0)≠0,where Q:Z→Z is a continuous projection as above with Im L=Ker Q and JNL:Im Q→Ker L is any isomorphism.

-Then the equation Ly=Ny hasat leastone solution in dom L∩Ω.

For convenience,we introduce some necessary definitions and resultswhich will be used in the article.

Definition 1[2]The fractional integral of orderα>0 of a function f:(0,∞)→is given by

provided the right side is pointw ise defined on(0,+∞).

Definition 2[2]The fractional derivative of orderα>0 of a function f:(0,+∞)→is given by

where n=[α]+1,provided the right side is pointw ise defined on(0,+∞).

Lemma 1[2]Assume x∈C(0,+∞)∩Lloc(0,+∞).Then

where ci∈R,i=1,2,…,n,n=[α]+1.

In this paper,we use the space X,Y defined by

+→[1,+∞)is a continuous strictly increasing function with g(0)=1,g(t)→+∞as t→+∞.Denote‖x‖1=‖x/g‖∞.By standard argument,we can prove that space (X,‖·‖X)(Y,‖·‖Y)are two Banach spaces.

We suppose the following conditions hold:

(H1)exists.

(H2)f:satisfy the SCarathéodory condition,that is,

(2)for a.e.t∈[0,+∞),(u,v)→f(t,u,v)is continuous on2;

(3)for each r>0,there existsφr(t)∈L1[0,+∞)∩BC[0,+∞)satisfyingφr(t)>0,t∈(0,+∞)such that max{‖u‖,‖v‖}≤r implies

By(H1),there exists constant M>0 such that

Lemma 2[12]Let D be a subset of Banach space(C[0,+∞),‖x‖1).

Then D is relatively compact in(C[0,+∞),‖x‖1),if and only if the follow ing conditions are satisfied:

(1)all functions from D are uniform ly bounded;

(2)all functions from D are equicontinuous on any compact interval of J;

(3)all functions from D are equiconvergent at infinity,that is,for any givenε>0,there exists a T=T(ε)>0 such that it holds

2 Main Results

In this section,we will establish the existence theorem for the sequential fractional differentialequation involving Riemann-Liouville fractional derivative.In order to prove our main results,we need turn the boundary value problem(1)to operator equation.

Define operator L:dom L∩X→Y as follows:

We define N:X→Y be setting N(x(t))=f(t,x(t),

We also define the linear projector operator Q:Y→Y as follows

whereω(t)∈Y satisfiesω(t)>0 andω(s)d s=1.It should be pointed that the definition of Q makes sense since y∈L1(0,+∞)∩BC(0,+∞),then

Lemma 3The operator L:dom(L)⊂X→Y is a Fredholm operator of index zero.The linear operator KP:Im L→dom L∩Ker P→Y can be w ritten as

also

ProofIt is trivial fact thatKer L={ctα-1,c∈R}.Now we show that

Actually,on one hand,let y∈Im L,there exists x∈Dom L such that y(t)=ByLemma 1,=x(t)+From the condition of the boundary value problem(1),we have

and thus On the other hand,suppose y∈Y satisfies Qy=0.Setting x(t)yields

By Qy=0,we know that

It follows from Eqs.(10)and(11)that x∈dom L andThat is to say,Eq.(9)holds.

For y∈Y,taking the projector Q:Y→Y as follows:

Actually,from Q1ω(t)=1,a simple computation shows that Q is a projector.Denote=y-Qy.It is easy to see that

It follows from Eqs.(9)and(12)that∈Im L and thus Y= Im L+Im Q.By y∈Im Q,there exists constant c∈such that y=cω(t),and by y∈Im L,Eq.(9)and Q1ω(t)=1,we obtain

This implies that Im L∩Im Q={0}and Y=Im L⊕Im Q.Thuswe have

which implies that L is a Fredholm operator of index zero.

Taking P:X→X as follows:

then the generalized inverse KP:Im L→dom L∩Ker P can be w ritten by

Actually,for y∈Im L,we have

and for x∈dom L∩Ker P,we know

It follows from x∈dom L∩Ker P,Together with Eq.(2),we get that c1=c2=0 which shows (KpL)x(t)=x(t).Therefore,

This combined with Formula(13)yields Formula(8).This completes the proof.

Lemma 4Let H2hold,then N is L-compact.

ProofObviously,QN and Kp(I-Q)N are continuous. So we only need to prove that QN and Kp(I-Q)N map bounded sets into relatively compact ones.

Suppose U is a bounded subsetof X,then there exists r>0 such that‖x‖X≤r for all x∈U and from(H2),we have

It follows from Formulas(15)and(16)that‖QNx‖Y≤2‖ω‖y‖φr‖L1.Noting that Im Q=2,we get QN is compact.Furthermore,for all x∈U,we have

It follows from Formulas(17)and(18)that KPQNU is uniform ly bounded.Meanwhile,for any fixed T>0,and for any 0≤t1<t2≤T,

Therefore,by Formulas(19)and(20),KP,QNU is equicontinuous.By Lemma 2,we can see that if KP,QNU/g(t)and LKP,QU are equiconvergent at infinity,then KP,QNU is relatively compact in X.In fact,considering the follow ing estimate

holds forε>0 and some L>0,where M is defined in Formula

(5).By(H1),we suppose that=a.Then we have

Thus,there exists T>L such that for t≥T,

Therefore,for t1,t2≥T,we get

So we complete the proof.

Theorem 2 Let the hypothesis(H2)hold and the follow ing conditions are satisfied.

(1)There exist functions a,b,c∈L1[0,+∞),c≠0,such that

(2)There exists constant A1>0 such that for x∈dom L, if for all t≥0,then

(3)There exists constant A2>0 such that for any c∈,either

or else

Then the boundary value problem(1)has at least one solution in space X provided that

ProofWe construct an open bounded setΩ⊂X that satisfies the assumption ofTheorem 1.Let

Ω1={x∈dom LKer L|Lx=λNx,for someλ∈[0,1]}.

For x∈Ω,we have x∈Ker L,λ≠0 and Nx∈Im L,then Ker Q=Im L.Thus Q(Nx)=0.By(2)ofTheorem 2,we know that there exists t∈[0,+∞)such that

It follows from the identityd s thatwe have

Again by x∈Ω,x∉Ker L,then(I-P)(x)∈Dom L∩Ker P and LP(x)=0,thus from Lemma 3,we have

where C=max By Formulas(25)-(26)and hypothesis(H1),we have

which implies that is, Ωis bounded.

LetΩ2={x∈Ker L:Nx∈Im L}.For x∈Ω2,x∈Ker L implies that x=ctα-1,where c is an arbitrary constant. Since QN(x)=0,

where Q is defined in Eq.(6).By the condition(2)ofTheorem 2,we getc≤A2,which impliesΩ2is bounded in X.

Define the isomorphism J:Im Q→Ker L as follows: J(cω(t))=ctα-1,c∈.

If the first part of condition(3)inTheorem 2holds,we set

For any x=ctα-1∈Ω3,one hasλ(cω(t))=λJ-1(x)= (1-λ)QNx.Ifλ=1,then c=0 and,ifc>A2,by the condition(3),it hasλc2ω(t)=(1-λ)ω(t)cQf(t,ctα-1,which contradictsλc2ω(t)>0.If other parts of the condition(3)hold,we take

and again,we obtain a contradiction.Thus,in either case

that is,Ω3is bounded.

SetΩbe an bounded open set such thatΩIt follows fromLemmas 3and 4 that L is a Fredholm operator of index zero and N is L-compactonΩ.By the definition ofΩandTheorem 1,it is sufficient to prove Eq.(3)ofTheorem 1is satisfied.To this end,let H(x,λ)=±λI d x+(1-λ)JQNx,where Id is the identical operator.By virtue of the definition ofthen by the homotopy property of degree,we obtain that

Thus,Eq.(3)of Theorem 1 is fulfilled and Lx=Nx has at least one solution in dom L∩∂Ω..The proof is complete.

3 Exam ple

Consider the boundary value problem

Taking A1=3,for any x∈X,assuming thatholds for t∈[0,+∞),then

The condition(2)ofTheorem 2holds.

It is easy to see that all c>0,we have

We also can prove that if c<0,there is cQf(t,ctα-1,tα-1)>0.The condition(3)ofTheorem 2is satisfied withc>4.So the boundary value problem(1)has at least one solution.

4 Conclusions

In this paper,by using the coincidence degree theory due to Mawhin and constructing the suitable operators,we obtain the existence result for infinity-point boundary value problem at resonance of nonlinear fractional differential equation.An example is presented to illustrate the result.

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O175.8

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1672-5220(2015)04-0665-07

date:2014-08-18

National Natural Science Foundation of China(No.11271248)

*Correspondence should be addressed to LIU Rui-juan,E-mail:ruirui0516@163.com