CHEN-RICCI INEQUALITIES FOR SUBMANIFOLDS OF GENERALIZED COMPLEX SPACE FORMS WITH SEMI-SYMMETRIC METRIC CONNECTIONS

HE Guo-qing

(School of Mathematics and Computer Science,Anhui Normal University,Wuhu 241000,China)

CHEN-RICCI INEQUALITIES FOR SUBMANIFOLDS OF GENERALIZED COMPLEX SPACE FORMS WITH SEMI-SYMMETRIC METRIC CONNECTIONS

HE Guo-qing

(School of Mathematics and Computer Science,Anhui Normal University,Wuhu 241000,China)

In this paper,we study Chen-Ricci inequalities for submanifolds of generalized complex space forms endowed with a semi-symmetric metric connection.By using algebraic techniques,we establish Chen-Ricci inequalities between the mean curvature associated with a semisymmetric metric connection and certain intrinsic invariants involving the Ricci curvature and k-Ricci curvature of submanifolds,which generalize some of Mihai andzgr’s results.

Chen-Ricci inequality;k-Ricci curvature;generalized complex space form;semisymmetric metric connection

2010 MR Subject Classification:53C40

Document code:AArticle ID:0255-7797(2016)06-1133-09

1　Introduction

Since the celebrated theory of Nash[1]of isometric immersion of a Riemannian manifold into a suitable Euclidean space gave very important and effective motivation to view each Riemannian manifold as a submanifold in a Euclidean space,the problem of discovering simple sharp relationships between intrinsic and extrinsic invariants of a Riemannian submanifold becomes one of the most fundamental problems in submanifold theory.The main extrinsic invariant of a submanifold is the squared mean curvature and the main intrinsic invariants of a manifold include the Ricci curvature and the scalar curvature.There were also many other important modern intrinsic invariants of(sub)manifolds introduced by Chen such as k-Ricci curvature(see[2-4]).

In 1999,Chen[5]proved a basic inequality involving the Ricci curvature and the squared mean curvature of submanifolds in a real space form Rm(C).This inequality is now called Chen-Ricci inequality[6].In[5],Chen also defined the k-Ricci curvature of a k-plane section of TxMn,x∈M,where Mnis a submanifold of the real space form Rn+p(C).And he proved a basic inequality involving the k-Ricci curvature and the squared mean curvature of the submanifold Mn.These inequalities described relationships between the intrinsicinvariants and the extrinsic invariants of a Riemannian submanifold and drew attentions of many people.Similar inequalities are studied for different submanifolds in various ambient manifolds(see[7-10]).

On the other hand,Hayden[11]introduced a notion of a semi-symmetric connection on a Riemannian manifold.Yano[12]studied Riemannaian manifolds endowed with a semisymmetric connection.Nakao[13]studied submanifolds of Riemannian manifolds with a semi-symmetric metric connection.Recently,Mihai andzgr[14,15]studied Chen inequalities for submanifolds of real space forms admitting a semi-symmetric metric connection and Chen inequalities for submanifolds of complex space forms and Sasakian space forms with a semi-symmetric metric connection,respectively.Motivated by studies of the above authors,in this paper we establish Chen-Ricci inequalities for submanifolds in generalized complex forms with a semi-symmetric metric connection.

2　Preliminaries

Let Nn+pbe an(n+p)-dimensional Riemannian manifold with Riemannian metric g and a linear connectionon Nn+p.If the torsion tensordefined by

for a 1-form φ,then the connectionis called a semi-symmetric connection.Furthermore, ifsatisfies=0,thenis called a semi-symmetric metric connection.Letdenote the Levi-Civita connection with respect to the Riemannian metric g.In[12]Yano gave a semi-symmetric metric connectionwhich can be written as

Let Mnbe an n-dimensional submanifold of Nn+pwith a semi-symmetric metric connectionand the Levi-Civita connection.On the submanifold Mnwe consider the induced semi-symmetric metric connection denoted by∇and the induced Levi-Civita connection denoted by∇＇.The Gauss formulas with respect to∇and∇＇,respectively,can be written as

for any vector fields X,Y on Mn,where h＇is the second fundamental form of Mnin Nn+pand h is a(0,2)-tensor on Mn.According to formula(7)in[13],h is also symmetric.

for any vector fields X,Y,Z,Won Mn,where α is a(0,2)-tensor field defined by

Denote by λ the trace of α.The Gauss equation for the submanifold Mnin Nn+pis

for any vector fields X,Y,Z,Won Mn.In[13],the Gauss equation with respect to the semi-symmetric metric connection is

In Nn+pwe can choose a local orthonormal frame{e1,···,en,en+1,···,en+p}such that restricting to Mn,e1,···,enare tangent to Mn.Setting=g(h(ei,ej),er),then the squared length of h is

The mean curvature vector of Mnassociated toh(ei,ei)and the mean curvature vector of Mnassociated to

Let π⊂TxMnbe a 2-plane section for any x∈Mnand K(π)be the sectional curvature of π associated to the induced semi-symmetric metric connection∇.The scalar curvature τ at x with respect to∇is defined by

The following lemmas will be used in the paper.

Lemma 2.1(see[13])If U is a tangent vector field on Mn,we have H=H＇,h=h＇.

Lemma 2.2(see[13])Let Mnbe an n-dimensional submanifold of an(n+p)-dimensional Riemannian manifold Nn+pwith the semi-symmetric metric connectionThen

(i)Mnis totally geodesic with respect to the Levi-Civita connection and with respect to the semi-symmetric metric connection if and only if U is tangent to Mn.

(ii)Mnis totally umbilical with respect to the Levi-Civita connection if and only if Mnis totally umbilical with respect to the semi-symmetric metric connection.

Lemma 2.3(see[10])Let f(x1,x2,···,xn)be a function on Rndefined by

If x1+x2+···+xn=2ε,then we have

with the equality holding if and only if x1=x2+xn+···+xn=ε.

A 2m-dimensional almost Hermitian manifold(N,J,g)is said to be a generalized complex space form(see[16,17])if there exists two functions F1and F2on N such that

for X,Y,Z,W on M,where M is a submanifold of N.

Let M be an n-dimensional submanifold of a 2m-dimensional generalized complex space form N(F1,F2).We set JX=PX+FX for any vector field X tangent to M,where PX and FX are tangential and normal components of JX,respectively.

3　Chen-Ricci Inequality

In this section,we establish a sharp relation between the Ricci curvature along the direction of an unit tangent vector X and the mean curvature||H||with respect to the semi-symmetric metric connect

Theorem 3.1 Let Mn,n≥2,be an n-dimensional submanifold of a 2m-dimensional generalized complex space form N(F1,F2)endowed with the semi-symmetric metric connectionFor each unit vector X∈TxM,we have

(1)

(2)If H(x)=0,then a unit tangent vector X at x satisfies the equality case of(3.1)if and only if X∈N(x)={X∈TxM:h(X,Y)=0,∀Y∈TxM}.

(3)The equality of inequality(3.1)holds identically for all unit tangent vectors at x if and only if in the case of n=0,i,j=1,2···,n;r=n+1,···,2m,or in the case of n=2,

Proof (1)Let X∈TxM be an unit tangent vector at x.We choose an orthonormal basis e1,···,en,en+1···,e2msuch that e1,···,enare tangent to M at x and e1=X.

When we set X=W=ei,Y=Z=ej,i,j=1,···,n,ij in(2.5)and(2.8),we have

Using(3.2),we get

We consider the maximum of the function

From Lemma 2.3 we know the solution()of this problem must satisfy

So it follows that

From(3.3)and(3.5)we have

(2)For the unit vector X at x,if the equality case of inequality(3.1)holds,using(3.3), (3.4)and(3.5)we have

The converse is obvious.

(3)For all unit vector X at x,the equality case of inequality(3.1)holds.Let X= ei,i=1,2···n,as in(2),we have

We can distinguish two cases:

(b)in the case of n=2,we have

The converse is trivial.

Corollary 3.2 If the equality case of inequality(3.1)holds for all unit tangent vector X of Mn,then we have

(1)the equality case of inequality(3.1)holds for all unit tangent vector X of Mnif and only if Mnis a totally umbilical submanifold;

(2)if U is a tangent field on Mnand n≥3,Mnis a totally geodesic submanifold.

Proof (1)For n=2,from Theorem 3.1 we know the equality case of inequality(3.1) holds for all unit tangent vector X of M2if and only if M2is a totally umbilical submanifold with respect to the semi-symmetric metric connection.Then from Lemma 2.2,M2is a totally umbilical submanifold with respect to the Levi-Civita connection.

For n≥3,from Theorem 3.1 we know the equality case of inequality(3.1)holds for all unit tangent vector X of Mnif and only=0,∀i,j,r.According to formula(7)from [13],we have+krgij,where krare real-valued functions on M.Thus we have=krgij.So Mnis a totally umbilical submanifold.

(2)If U is a tangent vector field on Mn,from Lemma 2.1 we have h＇=h.For n≥3, from Theorem 3.1 the equality case of inequality(3.1)holds for all unit tangent vector X of Mnif and only if=0,∀i,j,r.Thus we have=0,∀i,j,r.So Mnis a totally geodesic submanifold.

4　k-Ricci Curvature

In this section,we establish a sharp relation between the k-Ricci curvature and the mean curvature||H||with respect to the semi-symmetric metric connect

Let L be a k-plane section of TxMn,x∈Mn,and X be a unit vector in L.We choose an orthonormal frame e1,···,ekof L such that e1=X.In[5]the k-Ricci curvature of L at X is defined by

The scalar curvature of a k-plane section L is given by

For an integer k,2≤k≤n,the Riemannian invariant Θkon Mnat x∈Mndefined by

where L runs over all k-plane sections in TxM and X runs over all unit vectors in L.From (2.6),(4.1)and(4.2)for any k-plane section Li1···ikspanned by{ei1,···,eik},it follows that

and

From(4.3),(4.4)and(4.5),we have

Theorem 4.1 Let Mn,n≥3,be an n-dimensional submanifold of a 2m-dimensional generalized complex space form N(F1,F2)endowed with a semi-symmetric connectionThen we have

Proof For x∈Mn,let{e1,···,en}and{en+1,···,e2m}be an orthonormal basis ofandM,respectively,where en+1is parallel to the mean curvature vector H.

From(3.2),we have

Setting||P||2=(Jei,ej).From(2.6),it follows that

Then equation(4.8)can be also written as

We choose an orthonormal basis{e1,···,en,en+1,···,e2m}such that e1,···,endiagonalize the shape operator Aen+1,i.e.,

and Aer=(),i,j=1······n;r=n+2,···,2m,traceAer=0.So(4.9)turns into

On the other hand,we get

which implies

From(4.10)and(4.11),it follows that

which means

Using Theorem 4.1 and(4.6)we can obtain the following theorem.

Theorem 4.2 Let Mn,n≥3,be an n-dimensional submanifold of a 2m-dimensional generalized complex space form N(F1,F2)endowed with a semi-symmetric connectionThen for any integer k,2≤k≤n,and for any point x∈M,we have

Proof Let{e1,···,en}be an orthonormal basis of TxMnat x∈Mn.The k-plane section spanned by ei1,···,eikis denoted by Li1···ik.

Then from(4.6)and(4.12),we have

Remark 4.3 For F1=F2=C(C is constant)in Theorem 3.1,we obtain a Chen-Ricci inequality for submanifolds of complex space forms with a semi-symmetric metric connection.

For F1=F2=C(C is constant)in Theorem 4.1 and Theorem 4.2,the results can be found in[15].

References

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容有半对称度量联络的广义复空间中子流形上的Chen-Ricci不等式

何国庆

(安徽师范大学数学计算机科学学院,安徽芜湖241000)

本文研究了容有半对称度量联络的广义复空间中的子流形上的Chen-Ricci不等式.利用代数技巧,建立了子流形上的Chen-Ricci不等式.这些不等式给出了子流形的外在几何量―关于半对称联络的平均曲率与内在几何量―Ricci曲率及k-Ricci曲率之间的关系,推广了Mihai和zgr的一些结果.

Chen-Ricci不等式;k-Ricci曲率;广义复空间;半对称度量联络

MR(2010)主题分类号:53C40O186.12

∗date:2014-09-13Accepted date:2015-11-09

Supported by the Foundation for Excellent Young Talents of Higher Education of Anhui Province(2011SQRL021ZD).

Biography:He Guoqing(1979-),female,born at Chaohu,Anhui,lecturer,major in differential geometry.