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Qualitative Analysis of a Antibiotic-resistant Bacteria Model with Different Respond Function∗

2015-05-16GAOYukunMehbubaRehim

GAO Yu-kun,Mehbuba Rehim

(College of Mathematics and System Sciences,Xinjiang University,Urumqi Xinjiang 830046,China)

0 Introduction

Antibiotic resistance is a growing public health concern worldwide.When a person is infected with an antibioticresistant bacterium,not only is treatment of that patient more difficult,but the antibiotic-resistant bacterium may spread to other people.When antibiotics don’t work,the result can be:longer illnesses,more complicated illnesses,more doctor visits,the use of stronger and more expensive drugs,more deaths caused by bacterial infections[1].

Therefore,antibiotic resistance is a serious and growing phenomenon in contemporary medicine and has emerged as one of the pre-eminent public health concerns of the 21st century,in particular as it pertains to pathogenic organisms(the term is especially relevant to organisms that cause disease in humans).There have been many researches in identifying and understanding the factors and biological phenomena responsible for the emergence and spread of drug resistance[2-6].

In order to provide useful insights into the understanding of underlying phenomena and of helpful guidance to related public health decisions,one needs to understand the dynamics of the spreading antibiotic resistance.Some health scientists have tried to obtain some insight in the Antibiotic resistance and the methods of eliminating this phenomena using mathematical modeling.Here,we mention for instance[7-12].Many mathematical models have been devoted to address this issue since then.Recently,progress in mathematical modeling of antibiotic resistance has been accelerated by combining modeling with experimental testing.Based on the new findings in a recent experimental study[11]that antibiotic resistant mutants of bacteria produce indoles to protect the wild strain bacteria,Wendi Wang et al.[13]formulated a mathematical model to describe the evolution of the wild strain,resistant strain and indoles with limited nutrient.The authors in[13]established conditions for co-persistence of both strains,Further analyzed and simulated also revealed some new phenomena not reported in Lee et al.[11],that is,periodic oscillations of the populations may occur within certain range of the parameters,and there exists bistability in the sense that a stable positive periodic solution coexists with a stable positive equilibrium.The nutrient uptake(consumption)rate in the model[13]is taken to be of the Monod(or Michaelis–Menten)form:mxS/(a+S).In this paper,based on the model(1)in[13],for wild strain of bacteria,we want to introduce Monod-Haldene type respond function,the model reads:

whereS,B1andB2denote the concentration of nutrient,wild strain of bacteria,and the antibiotic resistant mutants,respectively.Aistherecruitmentrateofnutrient,disthewashoutrateofnutrientandbacteria,miistheMichaelis-Menten constant,γiis the yield constant representing the conversion efficiency of nutrient to the biomass of the organism,µiaccounts for the maximal growth rate,ε1is the death rate of wild bacteria due to antibiotic in fl uences and ε2is the death rate of its mutants under the antibiotic stress.η/hindicates the maximum absorb rate at which the wild strain bacteria absorbing the indoles.

All the parameters in the model(1)are non-negative in order to have a biological signi ficance.We also assumeµ2<µ1to account for the cost of resistant strain,and assume ε2<ε1to re fl ect the bene fit of antibiotic resistance.

1 Mathematical analysis of the model

Here,we first consider the existence and boundedness of solutions of system(1).And then the stability of the equilibrium points of system(1)are analyzed.This analysis allows us to better understand the role of the altruistic behavior of the resistant bacteria observed in Lee et al[13].In order to do this,we shall consider the following threshold parameters values:

1.1 Positivity and boundedness of solutions

Theorem 1The solution(S(t),B1(t),B2(t),I(t))of system(1)with initial conditionS(0)≥0,B1(0)≥0,B2(0)≥0,I(0)≥0 exist and positive on(0,+∞).Further,

1.2 Existence and stability of the boundary equilibrium

In this section,the equilibrium points of the model are calculated.Obtaining the equilibria is usually the first step in order to know the behavior of a dynamical system.Speci fically,it is shown that the model has an bacterium-free equilibriumE0(S0,0,0,0),thenSinceFrom this we obtain thatR1>1.Therefore,the following results is easy to veri fied

IfB2(t)=0,thenI(t)=0 since indolesI(t)produced by resistant bacteriaB2(t).Thus,if>1,i=1,2,there are two boundary equilibriaE1=(S1,B10,0,0)andE2=(S2,0,B20,I2)in Ω.Where

Here,we consider the local stability ofE1andE2,which gives the thresholds for small invasions of wild strain and resistant strain respectively.

Theorem 2The following statement hold:

(a)Bacterium-free equilibriumE0is asymptotically stable if<1 and is unstable if>1 or>1 or borth of>1,i=1,2.

(b)Assume>1.ThenE1is asymptotically stable if<1,and is unstable if>1.

(c)Assume>1.ThenE2is asymptotically stable if<1,and is unstable if>1.

ProofAt the Bacterium-free equilibriumE0(S0,0,0,0),the Jacobian matrix is

The roots of the characteristic equation of det

Thus,(a)follows from(3).

Obviously,det(λE−J22)=0 has two eigenvalues λ1=(d+ε)(R3−1),λ2= −d−ε4<0.If<1,then λ1<0.Sincetr(J11)<0,det(J11)>0.Thus,the eigenvalues ofJ11have negative real part.Therefore,assumption<1 yields local stability ofE1.

Similarly,we can show thatE2is stable if<1.

Theorem 3Assume>1 and<1,and following inequalities hold true:

ThenE2is globally asymptotically stable in the set Ω ={(S,B1,B2,I):S>0,B1≥0,B2>0,I>0}.

ProofWe de fine a Lyapunov function by

Calculating the derivative ofV1along solutions of(1),we obtain

From(4)and(5),together with Theorem 1,we have

for all large enough t.

Let

setting

Then

since µ2−µ >0,µ2>d+ε,we haveF(S)<0.Hence,<0.Moreover,it also implies thatF(S)=0 if and only if

Set

Note that>1 impliesS0>S2.So

Hence,it leads toB1(t)=0.We further obtainB2(t)=B20,I(t)=I2.Thus,the largest invariant set of(1)contained inD1is{E2}.By the LaSalle theorem,all solutions of(1)in Ω approachE2ast→∞.

Theorem 4Assume>1 and<1.ThenE1is global asymptotically stable in the set Ω={(S,B1,B2,I):S>0,B1≥0,B2>0,I>0}if the following condition holds:

proofFirst we de fine a Lyapunov function by

Calculating the derivative ofV2along solutions of(1),we obtain

It is easy to see that(6)implies

for 0

Let

By similar discussions toE2,we see thatG(S)<0,for 0

Remark 1Theorem 3 shows that if the removing rate of the nutrient and bacterial,converting efficiency of nutrition to biomass and maximum growth rate satisfy certain conditions,then the wild type strain to become extinct,and antibiotic resistant mutants and indole will tend to be constant.

1.3 Existence and Stability of the interior equilibrium

In this subsection,we will look for conditions under which there exists a positive equilibrium for(1),accounting for co-existence of the two strains.

SinceR2>1 yields

it follows that populationB2will go extinct ifµ2≤(d+ε).Consequently,the indole populationI(t)is eliminate.So,in the following discussion,we assumeR2>1.

Letbe any positive equilibrium of system(1).Then the positive equilibrium point satis fies

It is difficult to solve the system(7),so,to be succinct,we suppose that both strains have the same metabolic parameters,i.e.,µ1= µ2= µ,m1=m2=m,γ1= γ2= γ.Thus,from(7)we can get the unique positive equilibrium poinwhere

I∗will be positive if and only if

Meanwhile,is the unique solution of the system

it follows from(9)thatandare positive if and only if

Then we have the following theorem

Theorem 5Assume that<2>1.If inequality(8)and(10)holds,then there exists an unique positive equilibrium

Theorem 6Assume that>1 andIf inequality(8)and(10)holds,thenE∗is locally stable.

ProofThe charecteristic equation of system(1)atE∗is

Where

where

ifµ>,then we havea1−d−ε4>0

Sincea1−d−ε4>0,we obtain ∆2>0,∆3>0.Therefore,it follows from the Routh-Hurwitz criteria thatE∗is locally asymptotically stable.

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